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Point X is on side
of such that , and . Find in degrees.Offline
Hi harrychess
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Hello:
Last edited by ElainaVW (2014-06-12 08:43:43)
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hi harrychess
Here's how I have done this:
Let AXB = ABX = a
and XBC = b
Now work out all the other angles in terms of a and b
CAB = 180 - 2a
CXB = 180 - a
XCB = a - b
Now use the given information and you'll get b easily.
Bob
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