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Matrix P =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
Can I just assume that the det=1 because it's just a re-arrangment of the identity matrix? Or does the mix up of order affect the determinent? thanks.
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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Can I just assume that the det=1 because it's just a re-arrangment of the identity matrix? Or does the mix up of order affect the determinent? thanks.
The determinant is indeed 1, but you must be careful. Here are some rules about how row (or column) operations affect the determinant of a matrix.
Let the matrix B be obtained from the matrix A by applying the row operation e. Then:
.These results hold true for the corresponding column operations.
For your matrix, the identity matrix has had two row operations: P(1,4) and P(2,3). So the determinant of your new matrix is (-1)*(-1)*1 = 1.
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