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#1 2006-04-07 06:09:44
- razor
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- Registered: 2006-02-24
- Posts: 6
proof
we have function g,in Real numbers dimension m and value p (with p=(p1,...,pm)) is positive.
For at least one p,that g(p)>zero or equal to zero or g(p)<zero or equal to zero,is true.Also,p*g(p)=0 for p positive.
Then,proof that g(p)=0.
Last edited by razor (2006-04-07 06:19:30)
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#2 2006-04-07 20:12:20
- George,Y
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- Registered: 2006-03-12
- Posts: 1,379
Re: proof
at least one p,that g(p)>zero or equal to zero or g(p)<zero or equal to zero,is true. --do you mean g(p) cannot be (-1,8,...)type?
g is a vector function?
at least one-- i can't use this special condition, lol
X'(y-Xβ)=0
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#3 2006-04-08 04:50:15
- razor
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- Registered: 2006-02-24
- Posts: 6
Re: proof
g is a vector function and g(p)>=0 or g(p)<=0.
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