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Neither do I, there is a thing called completing the cube and I have post somewhere about it but I do not rememeber how I did it then. I use trial and error.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I know of completing the squre, can't it be possible if I use the quadratic formula?
Last edited by EbenezerSon (2014-09-02 01:28:03)
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The quadratic formula is for quadratics not cubics. One way is deflation.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The book has zero as the answer at the back
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That is one answer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, it is zero [0] that its answer at the back.
I know only one thing - that is that I know nothing
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But I will try to invent completing the cubic formula from competing the square formula, and use it
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You do not have to that cubic is readily factorable.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I am stuck I can't do it
I know only one thing - that is that I know nothing
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Hi;
(m-1) (m^2+m-3)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I must learn how to factor cubics
I know only one thing - that is that I know nothing
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Have you learned how to graph functions?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Please sorry if I am bothering you much - if yok wouldn't mind I will like to learn your steps once and for all.
Thank you very much
I know only one thing - that is that I know nothing
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Have you learned how to graph functions?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Have you learned how to graph functions?
No
(Sorry I was interrupted)
Last edited by EbenezerSon (2014-09-02 09:31:00)
I know only one thing - that is that I know nothing
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There is a formula for a cubic just like the quadratic one but it is much more involved.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks Bobbym,
I wish I learn it! Because in case of any cubic equation I can't do it
Last edited by EbenezerSon (2014-09-03 17:43:15)
I know only one thing - that is that I know nothing
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Here is the method for completing the cube. It is a mess!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thank you
But the link could not open for me when I try it says "the search returned no hits" I don't understand why that.
But I would like to put this across, in fact the x^2 has me thinking about it,
Find the truth set of the equation;
3^(x^2 + 2) = 27^x
Last edited by EbenezerSon (2014-09-05 06:32:12)
I know only one thing - that is that I know nothing
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Howdy;
Take the log of the both sides.
You can solve for x from here.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
2logx - log3x + log2 = 0
x(2log10 - log3) = -log2
x = -log2/(2log10 - log3)
Is this correct?
Last edited by EbenezerSon (2014-09-06 01:05:10)
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The second line appears wrong. You can not just pull the x out of log(3x). In other words log(3x) does not equal x log(3).
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Then see;
logx^2 - log3x + log2 =
log( x^2/3x) = -log2 > law of logarithm.
logx^2 = -log2*log3
Is this steps correct?
Last edited by EbenezerSon (2014-09-06 05:52:53)
I know only one thing - that is that I know nothing
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This is correct up to here:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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In fact, I am stuck, please help.
I know only one thing - that is that I know nothing
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