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Hi,
I'm trying to solve a math problem and could use some help. I need to find a way to calculate the following.
My formula is this: a * (1+ ∑ b^n) = Sn
My knows are a, b and Sn. My unknown is n.
So for example:
a = 4
b = 1.07
Sn = 23
calculate n
answer n = 4
explained:
S4 = 4 * (1+ ∑ 1.07^n) = 23
Since ∑ 1.07^n = 1.07 + 1.07^2 + 1.07^3 + 1.07^4 = 1.07 + 1.145 + 1.225 + 1.311 = 4.7507
4* (1+4.7507) = 23.00
So how can I derive n for any set of variables?
Thanks!
hi Nico van Os
Welcome to the forum.
is a geometric series and there's a formula for that.
If you make b^n the subject of the equation (and it's not obvious what n is) then take logs to make n the subject.
eg.
Hope that helps,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Take logarithms.
Last edited by Olinguito (2014-09-17 20:24:02)
Bassaricyon neblina
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Hi guys,
Thank you so much for helping me. This solved my problem. :-))
Question: how do you produce these formula notations? I can't find any explanation.
Math is indeed fun. Some formula's are still like magic to me.
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You can get those neat looking formulas using LaTeX.
To use it, you need the math tags:
You can click any formula to see how it was written. Also, there are a lot of them here
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Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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