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Hi,
Here is some diagram:
Let the length of the straight orange line be X=1
The rest of the non-straight orange lines (in this particular case, the non-straight orange lines have forms of different degrees of Koch fractal) are actually the same line with length X=1 ,such that its end points are projected upon itself, and as a result we get the convergent series 2*(a+b+c+d+...).
By using the definition of Limit as used by Real-analysis X-2*(a+b+c+d+...)=0, but 2*(a+b+c+d+...) is the projected result of infinite amount of non-straight orange lines (where each one of them has the length X=1).
Since length X=1 is invariant upon infinite amount of non-straight orange lines, how (by using the definition of Limit as used by Real-analysis) one concludes that 2*(a+b+c+d+...) = X ?
Last edited by Line (2014-10-18 15:20:32)
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Well, let us assume at each step the original line is broken into fragments of equal length. After the first step we have 4 fragments of length 1/4, after the second we have 16 fragments of length 1/16, etc. Then we have
[list=*]
[*]
Hence
[list=*]
[*]
Last edited by Olinguito (2014-10-18 22:42:34)
Bassaricyon neblina
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But 2*(a+b+c+d+...) (which is the result of the projection of length X=1 upon itself) is actually 1 only if the projected non-straight line is collapsed into length 0.
This is definitely not the case in the diagram above (there are infinitely many non-straight lines, where each one of them has length X=1).
So, I still do not understand how 2*(a+b+c+d+...)=X by your string of notations.
Moreover, if length X=1 is defined in terms of the set of all R members in [0,1], and [0,1] is invariant (exactly as X=1 is invariant in the diagram above), then how exactly |R| is collapsed into cardinality 1 (which is the cardinality of the set with a single member (the vertex at the bottom of the big triangle))?
Last edited by Line (2014-10-19 06:20:09)
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