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Wow!
I confronted a math tutor - but he claimed the answer 1/3 or -1/3 is correct - now I Could realise that your method is good. Please I want the tutor to see for himself your steps because he was insisting that the books' answer is correct
Thanks bobbym
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Is it logs to the base 10? The common log?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The book says - if the base is not written then it is base 10. And with this problem the base is not written - so it used base 10
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Ask the tutor to plug and check his answer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I am away from the tutor now - but I shall tell him later
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Yes, I am very interested in his answer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Still I haven't come across the tutor - but I will definitely meet him.
My one question is - when do one take antilogs of both sides of an equation?
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I would say when doing it is easy and helps with the simplification of the equation. Generally, I do the simpler stuff first like addition and subtraction of like terms.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I think your methods are good concerning the simplification of like terms in logs. Thanks for answering.
Look it if it is good
log16^-x = log2 + log7
-xlog16 = log14
x= -log14/log16
Is it good?
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Hi;
I am getting that too.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks! Bobbym
I am now getting logarithm better.
See;
solve for x in, log16^x.
log16^x = 10
xlog16 = log10
x = log10/log16
correct?
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Hi;
That is not correct, work on line 2.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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xlog16 = log10
xlog16 = 1
x = 1/log16
Correct?
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Is this xlog16 = log10 the original problem?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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No, the original is log16^x.
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log16^x = 10
Do the operation on the left.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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like this;
xlog16 = 10
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That looks right.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Again;
x = 10/log16
correct?
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That is correct.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Good!
Thanks bobym - I will post problems.
Big thanks!
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I am going to take a little break to have some panko breaded chicken. See you in a bit.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ok. Let me put this
Log(x-3) - logx = 2.
Is negative one (-1) the correct answer?
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Hi;
Did you plug that answer in to check it?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I have plug it in and the calculator gave me "math error". But I want to add that the base is five [5] for all.
Last edited by EbenezerSon (2014-10-25 21:34:30)
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