Rational Equation

CIV · 2014-11-09 15:06:46

For the life of me I can't figure out how to solve this problem. Please help me understand this.

1/(k+2) - 4/(k-2) - k^2/(4-k^2) = 0

I got as far as this: -k^4 + 3k^3 + 14k^2 -12k - 40 = 0

I can't figure out what's next or even if I came to the correct point. I've wasted so much time trying to figure this out. I have to skip it and move on to complete my homework.

Thanks in advance:) Oh by the way,... I love this website!!! So helpful! I use it all the time.

bobbym · 2014-11-09 16:00:39

Hi;

You should notice that,

you should be able to finish now.

CIV · 2014-11-09 16:07:08

It's funny because i did notoce that. I know that the opposites such as (2-k) and (k-2) when one is in the numerator and one is in the denominator they cancel out and leave behind a -1. I forgot you could do what you showed me:) Thanks:)

Hey, how do you post the arithmetic the way you did? As oppose to the way I did it.

bobbym · 2014-11-09 16:12:03

There is a page that does it all for you:

http://www.codecogs.com/latex/eqneditor.php

let me know if you need help with it and welcome to the forum.

CIV · 2014-11-09 16:16:32

Awesome. Thanks so much. Going to save that site for future use. I know I'm to need it and this site again:) Thanks again:)

bobbym · 2014-11-09 16:30:37

It is a nice site and you are welcome.

Math Is Fun Forum

#1 2014-11-09 15:06:46

Rational Equation

#2 2014-11-09 16:00:39

Re: Rational Equation

#3 2014-11-09 16:07:08

Re: Rational Equation

#4 2014-11-09 16:12:03

Re: Rational Equation

#5 2014-11-09 16:16:32

Re: Rational Equation

#6 2014-11-09 16:30:37

Re: Rational Equation

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