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Sir, the question is what is the total of nth row of the followingdistribution of the natural numbers.
1
2 3
4 5 6
7 8 9 10
... .. ... ... ....
... .. ... ..... .... ....
please guide me with a formula that can be used in this.---Regards--Balaji
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Hi;
This problem has already been solved:
a(n)=(1/6)*(3*n^3+3*n)
http://oeis.org/search?q=1%2C5%2C15%2C3 … &go=Search
Post back if you can not wade through their work.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Let T(n) represent the nth triangular number; then the nth row is
[list=*]
[*]
Hence the sum is
[list=*]
[*]
Bassaricyon neblina
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