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That makes a difference.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ask the tutor to plug and check his answer.
Yes - have seen the tutor - the tutor gave me a calculator which I plugged 1/3 into the equation and I had 1(one), so it seems his answer is correct. What do you say Bobbym?
Last edited by EbenezerSon (2014-11-24 21:26:15)
I know only one thing - that is that I know nothing
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Please rewrite the question, I have forgotten which one you are talking about.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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This is it;
log(x^2 + 1) - 2logx = 1
I know only one thing - that is that I know nothing
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The logs are common or natural?
Also that is not the equation you gave in post #664. In post #664 you gave this equation
log(x+1) - 2logx^2=1
That is the equation I said does not have a root of 1 / 3.
Now you are giving this equation.
This is it;
log(x^2 + 1) - 2logx = 1
They are not the same.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Show that
Log x = 1/2logx and hence solve log x + 1/2 = logx
In both cases the LHS is in base 4 and the RHS is in base 2
Thanks
Last edited by EbenezerSon (2014-12-01 06:48:02)
I know only one thing - that is that I know nothing
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Please, help.
I don't understand the question.
Last edited by EbenezerSon (2014-12-01 06:50:11)
I know only one thing - that is that I know nothing
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Hi;
Sorry, I was away pretty much all day. Where are you stuck?
Looks like the first thing you should do is convert those weird logs to the natural log and then you should have no problem.
Do you know how?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
I am given it a try concerning the conversion;
Log x = 1/2log x
so, it will be
log (x) = 1/2log (x)
Is that correct?
Last edited by EbenezerSon (2014-12-03 02:37:16)
I know only one thing - that is that I know nothing
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I can not say. Please bracket the expression.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I have bracket
I know only one thing - that is that I know nothing
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The new equation is not the same.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I have made the amendment- thank you
I know only one thing - that is that I know nothing
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That is true but it is an extremely complicated and cumbersome way to do the problem.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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