You are not logged in.
Hello again mathisfun and welcome to fun with circles:
Question 19 in my textbook has me a little bit stuck. It goes like this:
I've done the first part of the question, but on the second part, I get an answer that disagrees with the book's and I'm not sure who's right.
This is what I've done:
.The gradient of the radius to A is:
Therefore, the equation of the tangent to C at A is:
Therefore, at the point of intersection:
I chose to eliminate y:
Sub x into (2)
But, my textbook has the opposite sign:
So: Who's right? If I'm right - well, that's nice If not: what've I done wrong? Get confused with signs? I wouldn't be too surprised, but I've checked several times!
Offline
hi Au101,
I'm getting your answer. My sketch had a > b and the tangents crossing on the positive y axis. (if a < b then on the negative). So the y coordinate has to be positive. Your answer agrees with this and the book answer puts the point on the negative y axis, so I'm going with your answer.
C1 is the mirror image of C in the x axis so the book answer is for C1. Could easily be a typo somewhere.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Thank you bob bundy, I really appreciate it! It can be a bit of a pain when you and the book are the only authorities to consult on your answer
Offline
Yes it can. But notice what I did to check. I was going to put in some numbers and construct it, but I realised it was sufficient to consider a>b and a<b to determine which answer was implausible. For a long time, bobbym had a piece of advice in his signature along those lines ... "check it with numbers" .
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline