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Hey thanks for answering. I was wondering if you could explain how you arrived at that answer. Also to clarify the equilateral triangles are on opposite sides of each other on the square. They both share the same length of A on the lines parallel from one another on the square.
Hello
Bobbym had to prepare dinner for three so he's going to be busy for a bit.
His method was to accurately compute the first 10 rhombuses and then curve fit which needed an ansatz that only he could see. This won't be the type of classical answer you require but at least you have the answer.
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That is exactly how I pictured it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Method by trig. in first post.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Argh;
I was wondering if you could explain how you arrived at that answer.
I gave an answer here.
The method I used was to deduct the area of the square from the sum of the areas of the four triangles that together fill the square, the result being the area of the only overlapped region: the rhombus.
Last edited by phrontister (2015-06-25 00:33:09)
"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson
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