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Why does cot^2(x) + 1 = csc^2(x) for any x such that x is not an integer multiple of 180 degrees, where cot=cotangent and csc=cosecant?
Cotangent=(cos(x))/(sin(x)) and Cosecant=1/(sin(x))
My understanding is (cos^2(x))/(sin^2(x))+1=1/(sin^2(x)), multiplying the equation by sin^2x to get;
cos^2(x)+sin^2(x)=sin^2(x), but that doesn't get me anywhere with why that's true for all x that's not a multiple of 180. A little help please?
Thanks
Girls can be just as good as boys at math. We just need to get the same encouragement.
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hi championmathgirl
Let's start with
Why is that true?
In right angled triangle trig, using Pythagoras
Divide by H squared
But we can also define sine cosine and tangent for angles beyond 0-90 by considering a unit circle centred on the origin and letting a point rotate around (0,0) :
defining sin(θ) = y coordinate of the point and cos(θ) as the x coordinate.
http://www.mathsisfun.com/geometry/unit-circle.html
As a result equation (1) continues to hold for all angles.
Now divide by sin^2(θ)
which is the same as
There's a third trig identity like these two which you can derive for yourself as an exercise
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thank you so much!
(i think I figured out the third... still working on it though!)
Girls can be just as good as boys at math. We just need to get the same encouragement.
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Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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