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Suppose $f(x)$ is a function defined for all real $x$, and suppose $f$ is invertible (that is, $f^{-1}(x)$ exists for all $x$ in the range of $f$).
If the graphs of $y=f(x^2)$ and $y=f(x^4)$ are drawn, at how many points do they intersect?
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hi Ridley-C
I thought I'd collect some data by choosing various functions:
(1) If f(x) = x, then the two graphs only intersect at the origin.
(2) If f(x) = 2x+ 1, there are three points of intersection.
(3) If f(x) = sin(x) then strictly it isn't invertible, but if you limit to [0,pi/2] then there are 5.
That's as far as I've got so far. Did you expect a single answer for all f(x) ?
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Oops I'm stupid xD
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