You are not logged in.
Pages: 1
So according to my textbook
|iz*/2 - i/2| simplifies to |z-1|/2
where z* is the conjugate of z.
I can't work out how they got that so could someone please show it to me.
Thanks.
Offline
hi mrpace
| iz*/2 - i/2 | = 1/2 . |z* - 1|
Say z = a + ib then z* = a - ib
z* - 1 = a - ib - 1 = (a-1) - ib
z - 1 = (a - 1) + ib
as the | | is just root of real^2 + img^2 these are the same.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Pages: 1