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#1 2015-09-16 19:10:29

mrpace
Member
Registered: 2012-08-16
Posts: 88

Simplifying complex numbers

So according to my textbook
|iz*/2 - i/2| simplifies to |z-1|/2

where z* is the conjugate of z.

I can't work out how they got that so could someone please show it to me.
Thanks.

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#2 2015-09-16 22:15:39

Bob
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Registered: 2010-06-20
Posts: 10,621

Re: Simplifying complex numbers

hi mrpace

| iz*/2 - i/2 | = 1/2 . |z* - 1|

Say z = a + ib then z* = a - ib

z* - 1  = a - ib - 1 = (a-1) - ib

z - 1 = (a - 1) + ib

as the |    | is just root of real^2 + img^2 these are the same.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2015-09-16 22:19:14

zetafunc
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Registered: 2014-05-21
Posts: 2,436
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Re: Simplifying complex numbers

It now remains for you to show that
.

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