Math Is Fun Forum

owenflo

Member

Registered: 2014-07-21

Posts: 115

Please help

1. If a hexagon has a side of 3 units, what is the area of the hexagon?

side= 3 units area of hexagon= (3xsqrt3 s2)/2

(3xsqrt3 32)/2

(5.2x9)/2

area= 23.4

2.If a hexagon has an area of 100 units, what is the length of one side?

area= 100 units formula= A= (3xsqrt3 s2)/2

100=(3xsqrt3 s2)/2

200=(3xsqrt3 s2)

200=(5.2x9s2)

200=23.4s2

200/23.4=s2

s2=8.55

3.If a hexagon has a radius (center to point of angle) of 6, what is the side of the hexagon?

radius=6 so each section is 60 degrees.

sin60(6)=5.2

a=bh/2 - (5.2x6)/2

area= 93.6      93.6=(3xsqrt3s2)/2

                      187.2=(3xsqrt3s2)

                      187.2/5.2=36/6=6

the side of the hexagon would be 6

5. If a hexagon is resting on a flat side, and has a total height of 18, what is the length of each side of the hexagon?

one side of a hexagon has 3 sides so if one side has a height of 18 then: 18/3 is 6. so each side would measure 6.

6.If a hexagon is resting on a flat side, and has a total height of 18, what is the area of the hexagon?

A = 9^2 x 6 * tan x (180/6)
A = 280.59

In problems 1-3, please explain the formula that you've used.

#5 is incorrect.  The height of a hexagon extends from midpoint of one side to midpoint of the opposite side.  It's different from the diameter of the hexagon, which extends from vertex to vertex.

#6  Please explain the formula that you are showing

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: Please help

Hi;

1) That is what I got.

2) You are supposed to get 6.2, please recheck your algebra.

These questions have already been asked and answered over here:

http://www.mathisfunforum.com/viewtopic.php?id=22493

Please use that thread.

---

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.