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1. Identify a function f(x) so that f(x). f(y) = f(x + y).
2. Prove that a . a^1/2 .a^1/4 .a^1/8. ... ... [infinity] = a^2
Got to go. I'll bring the rest later.
Thanks
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hi math9maniac
Q1. logs have this property. http://www.mathsisfun.com/algebra/expon … ithms.html
Q2. To multiply numbers written as powers you add the powers:
So the whole expression 'hinges' on being able to write a single expression for
See here http://www.mathsisfun.com/algebra/seque … etric.html
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Logs don't have that property, exponentials do
'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'
'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
I'm not crazy, my mother had me tested.
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Ok. Thanks so much guys for these. Here are the others.
3. Find two numbers such that their arithmetic mean is 15 and Geometric mean is 9 without using the identity (a + b)^2 = (a - b)^2 + 4ab.
4. If tanA = 1/3 and tanB = 1/2, prove that sin 2(A + B) = 1.
5. If A = {(x, y): y = a ^x, x € R } and B = {(x, y) : y = a^-x, x € R }, then what is A n B?
PS. : I have used € to represent the mathematical symbol " belongs to " or " is a member of "; n in place of "the intersection " symbol. I don't have these on my keyboard. Thanks for understanding.
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Logs don't have that property, exponentials do
Whoops. embarrassed smiley. Thanks Agnishom. Glad to see at least you are awake.
Q3. So put (a+b)/2 = 15 and ab= +/- 3 and solve.
Q4. There's a formula that will give you a start:
Then you can convert to a sine by setting 'opp' = numerator and 'adj' = denominator, and calculating 'hyp' using Pythagoras.
Finally:
Q5. Compare the graphs by using http://www.mathsisfun.com/data/function … ?func1=2^x
Experiment with different numbers than a=2.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks zetafunc. I seemed to have caught inverse function disease. I wonder if there is a cure.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks so much.
Sorry to say that I still don't understand #1.
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Other questions to think about:
How about , , or for some ? Can you think of any similar functions that also satisfy this property?If you wanted to be a bit cheap, you could also say that is a valid solution.Offline
Ok zetafunc. Thanks for reply. Please how does f(x) = 0 satisfy the condition. Or in other words, how is it a valid solution?
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6. Find the domain and range of the function
f(x) = (x + a)/(a + 1 - x)
where a is a positive integer.
Thanks
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Ok zetafunc. Thanks for reply. Please how does f(x) = 0 satisfy the condition. Or in other words, how is it a valid solution?
If f(x) = 0 for every value of x, then that means that whatever I put inside the brackets gives me zero, e.g. it's also true that f(2) = 0, f(0) = 0, f(y) = 0, f(x + y) = 0. It is then trivially true that f(x)f(y) = f(x + y), since both sides of that equation are 0. However, this is usually called a "trivial solution" -- so some question-writers like to ask you to find the "non-trivial solutions".
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Ok. So what then are the non-trivial solutions?
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Can we also relate the function
f:x==> a^x
f(x) = a^x
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hi math9maniac
My apologies for earlier slipups. As a penance I set myself a task that I have now completed.
If you know the properties of the power function, then all you have to do is to show it fits this equation. But what if you have not met it before or want to get it as an answer without knowing in advance that it works. To find a way to derive the power function as the solution was my penance. Here is my answer:
Set y = 0 then
Now set y = -x
now set y = x
and setting y = 2x
continuing this we see that
Now put x = 1
So the power function is a solution. n is a positive integer If I could show that n may also be a fraction or real number then I'd have shown that only the power function works. This is a work in progress.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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put x = 1/2
f(1/2).f(1/2) = f(1/2 + 1/2) = f(1) = a
so f(1/2) = square root(a)
Similarly f(1/3) = cube root(a) and so on.
Thus f(n/m) is a^(n/m)
All real numbers lie between two rationals
eg. 31/10 < pi < 32/10
Further these bounds can be narrowed
eg. 314/100 < pi < 315/100
So f(r) can be determined to any degree of accuracy where r is real by determining a pair of rationals q1 and q2 either side of r and computing f(q1) and f(q2). Improved accuracy can always be achieved by narrowing the bounds q1 and q2.
Thus f(x) is determined as a power function for all x. The case discussed in an earlier post is just when a = 0.
Thus the general solution if f(x) = a^x for some constant a.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks so much Bob. I appreciate this.
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Q7. Three cars are there in a race. Car A is 3 times as likely to win as car B. Car B is twice as likely to win as car C. What is the probability of each car winning?
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hi math9maniac
You could call the probability of C winning 'p'. Then write the prob. for B and for A in terms of p.
If you then assume there are no other outcomes (like a draw), the three probabilities must add up to 1.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Wow, that seems quite easy but far from what I thought initially. Thanks a bunch.
I'll see you later for a piece of advice. Gracias
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