You are not logged in.
Hi, some problems that I don't know how to do. For (1), it says to use Power of a Point
(1) Circles with centers at O and P have radii 2 and 4, respectively, and are externally tangent. Points A and B on the circle with center $O$ and points $C$ and $D$ on the circle with center P are such that AD and BC are common external tangents to the circles. What is the area of the concave hexagon AOBCPD
(2) The length of each edge of a cube is 10 cm. and point K is placed at the center of a face of the cube. A line is drawn through the cube, as shown, from point K to point J, a vertex of the cube on the opposite face. What is the length of KJ? Express your answer in simplest radical form.
(3)
has side lengths x-1, x+1 and x+3. For what value of x is a right triangle?Offline
Never mind. Don't do number (3) and (2). I already figured it out. It is easy once you use you brain.
(3)
Solve it for x=7
(2) Drawing a line from K to the vertice above J gives a right triangle. Now use multiple Pythagorean Theorems
Last edited by evene (2015-11-20 11:35:04)
Offline
Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Although (1) is something that I need help on
Offline
Hi;
See of you can work your way to this answer...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Finally, I finished it. I just drew an extra line from O to DP so it's perpendicular!
Offline
Equilateral triangle
and a circle with center O are constructed such that BC is a chord of the circle and point A is the circumcenter of BCO in its interior. If the area of circle with center O is 48 pi, then what is the area of triangle ?Let ABCD be a square, and let M and N be the midpoints of BC and CD}, respectively. Find sin of angle MAN.
Offline
Hi;
Let ABCD be a square, and let M and N be the midpoints of BC and CD}, respectively. Find sin of angle MAN.
I am getting 3 / 5.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
hi evene,
The first circle is too large to show fully. As you know its area you can work out its radius, OB.
The triangle ABO is isosceles so you can split it in half to create a right angle and then use Pythagoras to calculate AB. From that it should be straight forward to work out the area of ABC.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
How do you get the height of
? When you split it in half, how to you get the height?Offline
Whoops! Sorry. Not Pythagoras but trigonometry. That dotted line cuts 60 in half so angle BAO = 150. So AB = half OB / cos(15)
Hope that helps,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
oh lol ok thanks
Offline
Sometimes my brain is so sure I've got it sorted I forget to pay attention to what I'm saying. I could see a calculation was possible there; just got the wrong one. I ought to have learnt by now but I haven't. In fact I seem to be getting worse. Just keep asking until I start making sense. .
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
I have a question about another alternative method I just thought up of:
Let the midpoint of BC be called M and let BC=a
and . So by Pythagorean Theorem, we haveNote: Refer to Bob's diagram above
Last edited by evene (2015-11-21 14:13:35)
Offline
Excellent!!!
Always better when you can make your own method and I like it better as it doesn't require cos(15). You meant BO^2 of course and you can say that directly from pi r squared.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Yeah that's what I meant, I'm sure that you got the idea
Offline
Ok so now, I just need help simplifying
EDIT: Noticed a mistake
Last edited by evene (2015-11-21 14:14:05)
Offline
Hi;
Expand the LHS out to:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Need help with this proof problem
Let
denote the circular region bounded by . The lines and partition into four regions . Let denote the area of region . If , then compute .Last edited by evene (2015-11-22 03:38:18)
Offline
I tried my best to simplify
and this is what I have. Can you verify if it's correct?Thank you for your patience
EDIT: Changed the mistake pointed out by Bob
Last edited by evene (2015-11-25 05:50:12)
Offline
I think that should be 3a^2 over 4 not 2.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Wow... another big bonehead moment for me...
Offline
No, no, no. Not bonehead. You got a special award (gold star) earlier. It just seemed to me that all those curves made it impossible, so there ought to be a way to get rid of them. Did you like the diagram ? Confucius, he say, "A picture is worth ten thousand words."
That's twice his name has come up in the last half hour.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Reminds me of a story:
Disclaimer: This excerpt is in no way putting down doctors, bigfoot or people in the old country.
I had just been in a bike accident where I was thrown off my bike at a speed of 30 mph ( I was going downhill ). My head contacted the pavement several times as I skidded down the street. The bike was skidding after me and kabonked me in the head too! I had some bruises and Doctor Vinny Boombotz, was amazed I was still alive. I calmy explained that I had been hit on the head with a pipe before with no effect.
He scoffed and dragged me over to his x-ray machine where they bombarded my cranium with the deadly rays. The film showed not a single fracture and he said I had an unusually thick skull , similar to a sasquatch skull. Now being compared to a bigfoot is an insult anywhere in the world but I overlooked it. I explained that all the m's were called boneheads back in the old country but we all thought that was just an insult.
Moral: It ain't so bad to be a bonehead.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
I have no idea what that means but I will curate it.
'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'
'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
I'm not crazy, my mother had me tested.
Offline