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Can this be factored or do you have to do quadratic formula?? Does the fact that it's an angle give it any unique workable properties or do I just look at coefficients like any other quadratic? Thanks.
1tan^2x + 3tanx -1 = 0
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Hi;
If you mean this:
then just make the substitution y = tan(x) and solve like any other polynomial.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, that's what I meant. Thanks.
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Did you solve the equation?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yup.
I just did x = b+/- blah blah to get tanx=.303 and -3.303.
So, tan^-1's =
16.86 degrees (.29 rad) and 196.86 degrees (pi+.29 rad).
And
286.84 degrees (1.28 + 2pi rad) and 106.84 degrees (pi - 1.28 rad).
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While concept was forming in my head, I was wondering if functions could change (x + y)(x + y) (factoring) vs quadratic approaches so that factoring might work where it doesn't without tangents, cosines etc...However, I realized that doesn't really make sense so that quadratic equation was necessary.
That was sort of the rationale behind my original question. I realize it's sorta nonsense tho. Factoring clearly wasn't going to work. Unless I'm missing something else...which, of course, is very possible. Lol
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You can always factor a quadratic, but not always simply.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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