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Each of the three circles in the figure below is externally tangent to the other two, and each side of the triangle is tangent to two of the circles. If each circle has radius three, then find the perimeter of the triangle.
[asy]
unitsize(0.5 cm);
draw(Circle(dir(90),sqrt(3)/2));
draw(Circle(dir(90 + 120),sqrt(3)/2));
draw(Circle(dir(90 + 240),sqrt(3)/2));
draw((1 + sqrt(3))*dir(90)--(1 + sqrt(3))*dir(90 + 120)--(1 + sqrt(3))*dir(90 + 240)--cycle);
[/asy]
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Last edited by evene (2016-02-27 10:30:03)
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Too bad you did not use Geogebra.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi tacowreck
Hope I've got this diagram right.
As DG = 3 and triangle ADG is 30-60-90, => AG = 3root(3). HC = same by symmetry.
DGHF is a rectangle so GH = 3+3 = 6
So AC = 6root(3) + 6.
evene's answer follows from this.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Yeah. You're diagram is correct. I plotted the Asymptote commands and it looks exactly like yours.
Give or take some lines.
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Thank You. I got it
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