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Two friends, Alexander and Byron, play the following game: they have 10 coins in a row in front of them and Alexander secretly selects two consecutive coins. Byron defines two subsets of the 10 coins which he presents to Alexander. Then Alexander tells Byron how many of the coins that he chose belong in each of the two subsets (for example, 2 coins in the 1st subset and none in the 2nd). Then Byron must guess, only by one attempt, the two coins that Alexander selected. Find a strategy such that Byron always wins.
Last edited by salem_ohio (2016-03-30 22:31:49)
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Must the cardinality of the 2 subsets equal 10?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Not necessarily
Must the cardinality of the 2 subsets equal 10?
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Okay thanks.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Cannot even imagine any solution!
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If I understand correctly choosing two subsets will split the 10 numbers into 3 pieces. Is that correct?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The two subsets plus the ones not belonging to any of the two subsets. Right.
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I have been unable to find a single solution. I will continue to work on it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Very intriguing puzzle though!
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Bobby, now that I think of it, the subsets can also be overlapping. I think that I am close to something...
If I understand correctly choosing two subsets will split the 10 numbers into 3 pieces. Is that correct?
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Overlapping? I do not understand.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I mean that the two subsets may also have some common numbers.
Overlapping? I do not understand.
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That changes things a lot.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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This is just my guess, maybe we must wait for Salem to confirm But it doesn't say "two different subsets"!
That changes things a lot.
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I do not see how having duplicates in the subsets is going to help anyway. What is needed is more subsets.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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OK, so:
Let's name the coins 1 to 10. We have 9 possible coin sets to guess: 1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9 and 9-10.
All possible answers that Alexander can give are 0, 1 and 2 (coins) for each subset, thus 9 possible combinations.
Let's take these two subsets for example: A: {3,4,5,9,10} and B: {5,7,8,9,10}.
Below we list Alexander's replies for each subset A - B and the set of numbers that Byron guesses:
A B
0 0 ----->1,2
0 1 ----->6,7
0 2 ----->7,8
1 0 ----->2,3
1 1 ----->5,6
1 2 ----->8,9
2 0 ----->3,4
2 1 ----->4,5
2 2 ----->9,10
So this way Byron can always win, no matter which pair of number Alexander has put in mind.
Last edited by anna_gg (2016-04-09 09:24:31)
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What happens if Alexander says (1,1) when he has picked 9,10?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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then he would have said 2,2 because both numbers (9,10) are in both subsets.
What happens if Alexander says (1,1) when he has picked 9,10?
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Hi;
I misunderstood the problem and that was a good reason why I could not solve it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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