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Part 1:
Let
and be polynomials.Suppose
for exactly three values of : namely, and .Suppose
for exactly five values of : namely, and .Is it necessarily true that
is divisible by ? If so, carefully explain why. If not, give an example where is not divisible by .Part 2:
Generalize: for arbitrary polynomials
and , what do we need to know about the zeroes (including complex zeroes) of and to infer that is divisible by ?(If your answer to Part 1 was "yes", then stating the generalization should be straightforward; try to prove it. If your answer to Part 1 was "no", then try to salvage the idea by imposing extra conditions as needed.)
Can you please help? And if you do, can I have an explanation for how to do it? Thanks.
Last edited by Enshrouded_ (2016-04-13 11:41:26)
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Hint: Do you see the factors of those two polys? Use that to show that f(x) will always divide g(x).
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I don't get how to see the factors. I know I need a polynomial q(x) so that g(x) = f(x) * q(x), but I don't know how to prove it exists.
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f(x) looks like this f (x) = b (x + 3) (x - 4) (x - 8)
g(x) looks like this g (x) = a (x + 5) (x + 3) (x - 2) (x - 4) (x - 8)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Oh I see. Thanks
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Wait but how do we know that b will divide a(x+5)(x-2)
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I think b and a are constants.
with a remainder of 0.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Wait, it's false because we could have say f(x)=a(x+3)^5(x-4)(x-8) and it wouldn't work. How do you show a way to determine polynomial divisibility from roots?
(The second part)
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f(x)=a(x+3)^5(x-4)(x-8)
You can not pick that because it does not have exactly 3 zeroes.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Complex roots must be in pairs
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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