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This property is given in my book.
The square of any determinant is a symmetric determinant.
Well it works when I take a determinant say 3x3 and multiply it by itself using row to row multiplication.
But it fails if I multiply using row to column.
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Debjit Roy
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The essence of mathematics lies in its freedom - Georg Cantor
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Hi;
Can I see an example?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I asked this question on other fourms but I didnt got any answer
Here is a link please read it https://www.physicsforums.com/threads/s … ic.873144/
Thanks
Debjit Roy
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The essence of mathematics lies in its freedom - Georg Cantor
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I am inclined to agree with fresh_42. A determinant is a scalar. It is one number.
For instance:
Symmetry in a number?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Well I too agree,but the problem is its not only in one book but rather more than one author is describing something like this.In that post I already gave some links to the books.
Debjit Roy
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The essence of mathematics lies in its freedom - Georg Cantor
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Matrices can be symmetric, determinants can not.
May I see your two calculations:
using row to row multiplication.But it fails if I multiply using row to column.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Perhaps the book isn’t putting things very clearly. IMO what it’s trying to say is that the square of a determinant is the determinant of a symmetric matrix. For instance:
[list=*]
[*]
Last edited by Alg Num Theory (2017-11-24 22:05:15)
Me, or the ugly man, whatever (3,3,6)
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