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Hi
This is my first post here.
I have a question regarding the equation below. How do I get from line 1 to line 2? I mean the part (1-e^x)^(-1) = (1+e^x+e^2x+e^3x+...)
Thanks for help.
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hi scs_t6
Welcome to the forum.
This is an application of (Newton's) generalised binomial expansion. You'll find it here:
https://en.wikipedia.org/wiki/Binomial_ … al_theorem
About half way down the page.
Hope that helps,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks! This helps, I see it now.
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I mean the part (1-e^x)^(-1) = (1+e^x+e^2x+e^3x+...)
How that was done would depend on the fellows age and his background. If he was around say 100 years old he would remember the Abramowitz Stegun book and the formula to invert a power series given in the early chapters. If he is a young fellow he probably would have used Mathematica and just failed to mention that.
But, if he was a generatingfunctionologist or a baby combinatoricist he would do it like this:
Remembering:
so he would substitute y = e^x and say
which when he substituted back
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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