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In triangle $ABC$, $\angle A = 36^\circ$ and $\angle B = \angle C = 72^\circ$. Let $\overline{BD}$ be the angle bisector of $\angle ABC$.
(a) Prove that $BC = BD = AD$.
(b) Let $x = BC$ and let $y = CD$. Using similar triangles $ABC$ and $BCD$, write an equation relating $x$ and $y$.
(c) Write the equation from Part b in terms of $r=\frac yx$ and find $r.$
(d) Compute $\cos 36^\circ$ and $\cos 72^\circ$ using Parts a-c. (Do not use your calculator!)
I was able to do a-c. Can I help on d?
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hint: Use cosine rule for the angles in
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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hi dazzle1230
This problem has been asked before here:
http://www.mathisfunforum.com/viewtopic … 83#p365383
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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I got that
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Well done!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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