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Find the Integral values of 'n' for which
{n+2} {n+2} / (n-3) is a natural number. Explain with logic please
Hi;
This is a bit rough but it will find solutions by inspection.
We say
where m >=0. Solving for n
by inspection we need an m that m - 20 is a square and m is a square. That immediately gives m = 36 and n = 4 and n = 28 those are the first two answers.
Of course you can get two more answers using m = 20 which yields n = 8. and m = 0 yields n = - 2
I leave to you the proof that these are the only 4 solutions.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Last edited by thickhead (2016-10-26 04:38:50)
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Let k = n-3 , then n = k + 3 .
( n+2 ) (n+2) = ( k + 5 ) ( k + 5 ) = k ^2 + 10 k + 25 .
For k to be a factor of ( n+2 ) (n+2) , it must be a factor of 25 ,
Thus k1 = 1 ⇒ n1 = 4 ;
k2 = 5 ⇒ n2 = 8 ;
k3 = 25⇒ n3 = 28 .
If 0 is accepted as a natural no . then n+2 = 0 ⇒ n4 = -2 .
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