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Is there a way to find the roots of x^3+x^2-10x-8=0?
I've tried substituting x with
but I got a really weird answer.Here is one way by completing the cube:
http://www.mathisfunforum.com/search.ph … 1038166535
And there is a formula in terms of the coefficients.
But as I have been saying to evene and corrupted, it is much easier to do numerically.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The link doesn't work.
If you wish to express the roots as the sums of cosines, then you use a prime number of the form p=6m+1. With m as the "number of cosines" that you use. So for you, we have p=31=6m+1. Thus, m=5. Meaning the roots are
Last edited by evene (2016-10-26 15:20:06)
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Hi;
I am sorry, try http://www.mathisfunforum.com/viewtopic … 00#p198900
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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