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Hello!
I've been trying to solve this proof, but only can provide examples, (e.g. y=2x^2). Could someone help me with the proof? Thanks!
Suppose f is a twice-differentiable function with f(0) = 0, f(1/2) = 1/2 and f ' (0) = 0. Prove that |f '' (x)| > or = 4 for some x in the interval [0,1/2].
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First use the MVT for f on the interval [0,1/2], and get an expression for f'(c) where c is some number in [0,1/2], using your initial conditions f(0) and f(1/2). Then use the MVT again on f' to get an expression for f'', and use the triangle inequality.
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Thanks zetafunc!
One question: in order to use MVT again on f' to get an expression for f", what value do I use for f'(1/2)? Do I use the f'(c) value that I found? [setting up MVT using f'(0) and f'(1/2)?]
Thanks!
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