simplify

Kiran · 2006-11-15 07:02:47

mathsyperson · 2006-11-15 07:53:35

Although that looks ghastly, it's actually not too hard. You just need to group all the x terms together and all the y terms together, work out what power each of them has and therefore what power of x and y multiplying all of them together would give.

For the x's, you have x^(1/3) * x^(3/4) on top, which is x^(13/12), and on the bottom you have x^-2 * x^(3/2) = x^(-1/2).

Dividing x^(13/12) by x^(-1/2) gives x^(19/12), so that is the x term of the final answer. You should be able to do the same thing for all the y terms now.

Kiran · 2006-11-15 10:08:06

ok thanks for the help now you are asking me to do teh y terms... is this what i did look right?

y * y^3/4 y^3/4
-------------- = -------- divide = y^-1/8 correct?
y^3 * y^-2 y^-6

mathsyperson · 2006-11-15 11:53:48

Not quite. The y on the top should be y^(1/2), because it's in a square root sign.

Also, when multiplying 2 numbers, you add their powers, don't multiply them. For example, x[sup]2[/sup] * x[sup]3[/sup] = x[sup]5[/sup], not x[sup]6[/sup].

Similarly, when you divide one number by another, you take the second power away from the first one.

Kiran · 2006-11-16 06:28:06

what do you mean take teh second power away form the first one?

i got
for top one > y^5/4
for bottom one > y^-6
now i have to divide i got -5/24

Monox D. I-Fly · 2016-12-15 20:53:17

No. You need to subtract the power, not divide them.

thickhead · 2016-12-15 21:16:00

Hi Monox,
Digging up 10 year old grave?

Monox D. I-Fly · 2016-12-16 13:54:44

Well, I didn't see any rules regarding necro-posting here. And whenever I did, neither bobbym and MathIsFun said anything about it.

thickhead · 2016-12-16 14:55:29

hi Monox D. I-Fly,
It was just for fun.I have neither objection ,nor any authority nor any intention to do so. My contention was it may not benefit the one who asked the question. I too have responded to queries 2 to 3 years back when the topic was found interesting.

Monox D. I-Fly · 2016-12-18 21:19:26

Then would you mind accompanying me robbing other graves?

Math Is Fun Forum

#1 2006-11-15 07:02:47

simplify

#2 2006-11-15 07:53:35

Re: simplify

#3 2006-11-15 10:08:06

Re: simplify

#4 2006-11-15 11:53:48

Re: simplify

#5 2006-11-16 06:28:06

Re: simplify

#6 2016-12-15 20:53:17

Re: simplify

#7 2016-12-15 21:16:00

Re: simplify

#8 2016-12-16 13:54:44

Re: simplify

#9 2016-12-16 14:55:29

Re: simplify

#10 2016-12-18 21:19:26

Re: simplify

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