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70=T+c
110=T+ce^(K/2)
145=T+ce^K
solve T = ?
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1) First, solve for K using your second equation:
2) Now, note that T=70-c and our K above, use your third equation:
Move over 70, and use that (110-T)/c = (c+40)/c (which you can get from 110=T+c+40 in equation 2)
But e^ln(a)=a, so
Which gives c=-320.
3) So T=70-c=70+320=390.
Last edited by numen (2006-07-26 07:59:42)
Bang postponed. Not big enough. Reboot.
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where does the 'e' dissapear off to?
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Last edited by Zhylliolom (2006-08-12 09:39:53)
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