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Inside a circle E there are 2 smaller circles A and B ,both with radius being 1/2 of that of E. Both A and B can move freely inside E .If a point is chosen randomly on E , find the probability that the point lies inside A and B at the same time.
Will the answer be simply 1/4 * 1/4 = 1/16 ?
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Hi;
I am getting results that suggest the answer is closer to 1 / 9. To check, are both of the smaller circles fully inside the larger circle?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym ,
The smaller circles must be fully inside the big one , they
cannot pass through its circumference .
If the answer is closer to 1 / 9 , then the result will be
the same as the case for rectangles .
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That I am not sure about. Where as the intersection of two rectangles was another rectangle, the area of the intersection of two circles involves trig functions. So, while I think the answer is close to 1 / 9 or 1 / 10, I do not think it equals a fraction.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Thanks thickhead ,
How did you get the result 1/4 - 4 / 3 π^2 , from integrals ?
I know that it is much more complicated to find the area of intersection of 2 circles , but it will be necessary to solve this problem .
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{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Hi thickhead ,
Then what will be P for 3 moving circles ?
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For 3 moving circles it is 0.0663554.
For 4 moving circles it is 0.0433163
For 5 moving circles it is 0.0305428.
For 6 moving circles it is 0.0227118.
For 10 moving circles it is 0.00948101
Last edited by thickhead (2017-03-08 16:11:20)
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Thus the probability for various polygons will be :
no. of moving polygons
P || 1 || 2 || 3 ||
________________________________________________________
circles || 1/4 = 0.25 || 1/4 - 4 / 3 π^2 = 0.1149 || 0.0663 ||
squares || 1/4 = 0.25 || 1/9 = 0.111 || 1/16 = 0.0625 ||
triangles || 1/4 = 0.25 || 1/10 = 0.1 || 1/21 = 0.0476 ||
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Related problem ( I )
Inside a circle E with radius e unit there are 2 smaller circles A and B with radius a unit and b unit respectively where a ≤ e and b ≤ e . Both A and B can move freely inside E . If a point is chosen randomly on E , find the probability that the point lies inside A and B at the same time.
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Related problem ( II )
On the surface of a sphere E with circumference being 1 unit there are 2 circles
A and B both with circumferences being 1/2 unit . Both A and B can move freely and randomly on the surface of E .
If a point is chosen randomly on the surface of E , find the probability that the point lies inside A and B ( referring from their minor portions ) at the same time .
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Related problem (III)
2 circles A and B both with radius 1 unit rotate freely and randomly
outside a circle E also with radius 1 unit on its circumference .
Find the expected value of the overlapping area of A and B .
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For the original problem , what will be the probability if both A and B cannot get
through the centre of E ?
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Last edited by thickhead (2017-04-02 20:45:22)
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Thanks thickhead ,
What will be the probability if A cannot get through the centre of E but B can ?
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Related problem (III)
2 circles A and B both with radius 1 unit rotate freely and randomly
outside a circle E also with radius 1 unit on its circumference .
Find the expected value of the overlapping area of A and B .
Can you clarify the question. Are the centers of A and B on the circumference of E or does each of them just intersect with E at one point ( circumference to circumference)?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym ,
I mean the circumferences of A and B rotate on the circumference of E . ( Just touch
at 1 point . )
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Was an answer given for this question yet?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym ,
No , I don't know the answer .
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Thanks. I have an answer but until I get the same answer using another way...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Related problem (III)
2 circles A and B both with radius 1 unit rotate freely and randomly
outside a circle E also with radius 1 unit on its circumference .
Find the expected value of the overlapping area of A and B .
Although problem (III) states that both A and B are movable .
But if one of them , say A is fixed touching E at a certain
point , with only B movable , the answer should be the same .
Thus the problem will become simpler .
A possible way to solve the problem is to consider the angle
between the centers of the 3 circles .
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the answer should be the same.
I agree and have been using that idea the whole time. Unfortunately, the computation of the integrals or sums is very difficult. The closest I can get right now is to say the expectation is about .43
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks thickhead ,
What will be the probability if A cannot get through the centre of E but B can ?
Product of the 2 probabilities integrated over the region gives the required probability.0.08618
http://www.wolframalpha.com/widgets/view.jsp?id=8ab70731b1553f17c11a3bbc87e0b605
{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}
(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha
{Gods rejoice at those places where ladies are respected.}
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Thanks bobbym and thickhead ,
For Related problem (III) , should there be a formula to calculate
the area of overlapping area of A and B if the angle between
the 3 centers being x degrees where 0 ≤ x < 60 ?
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