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In triangle ABC, the medians AD,BE, and CF concur at centroid G.
(a) Prove that AD < (AB + AC)/2.
(b) Let P=AB+AC+BC be the perimeter of triangle ABC. Prove that 3P/4 < +AD+BE+CF < P
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hi alext
Welcome to the forum.
Your problem has been posted before (and answered).
http://www.mathisfunforum.com/viewtopic.php?id=23062
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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