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Can anyone assist with the following problem to find a where x = 0.85, k=1 and y = 11.2;
y=ae^-k*x
Thank you
hi Trigtrigger
Welcome to the forum.
Can anyone assist with the following problem to find a where x = 0.85, k=1 and y = 11.2;
y=ae^-k*x
Please see next post by Alg Num Theory. I'll leave mine as a testament to the importance of 'reading the question' !!!
So 11.2 = a^(-0.85)
If you take logs (any will do but let's use base 10 as it's handy on a calculator) you get
log(11.2) = log(a^-0.85) = -0.85 * log(a)
So re-arrange this to make log(a) the subject, and inverse log it (ie. raise 10 to the power of) and you'll get a.
eg. If log(a) = 2 then a = 10^2 = 100
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Can anyone assist with the following problem to find a where x = 0.85, k=1 and y = 11.2;
y=ae^-k*x
So 11.2 = a^(-0.85)
Last edited by Alg Num Theory (2018-01-12 16:14:28)
Me, or the ugly man, whatever (3,3,6)
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Thanks Alg Num Theory. I seem to have lost an 'e'. Thanks for the correction. I have edited my post as a penance.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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