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Let f(x) be a quartic polynomial with integer coefficients and four integer roots. Suppose the constant term of f(x) is 6.
(a) Is it possible for x=3 to be a root of f(x)?
(b) Is it possible for x=3 to be a double root of f(x)? Prove your answers.
Is there a way to prove this question with the Rational root theorem?
Edit 2: I solved (a) but I'm not sure how to solve part (b)
Last edited by G123 (2018-04-06 05:47:53)
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hi G123
Welcome to the forum.
Yes, you can use the rational root theorem. You'll find it here:
https://en.wikipedia.org/wiki/Rational_root_theorem
If that leaves your head spinning let's simplify by looking at a quartic equation.
If p/q is a rational solution, ie p and q are integers
and if we times by q^4
If we assume p/q is in its lowest terms then => q divides a and p divides e.
But you are told that the solutions are all integers; as all integers are rationals this means that q = 1 and p divides e.
So could p be 3 ? Yes as 3 divides 6
Could p be 9 (ie a repeated root of 3) ? No because 9 doesn't divide 6.
Hope that helps,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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