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Find all real solutions for
I could use detailed help and/or a solution, the sooner the better.
The only work I have is simplifying and proving that 2^x - 1 and x have the same sign.
Thanks!
!nval!d_us3rnam3
Last edited by !nval!d_us3rnam3 (2018-07-27 03:25:21)
"If we wanna be great, we can't just sit on our hands" - 2017 NFL Bears draft
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There are precisely three solutions:
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Unfortunately I do not know how to prove it rigorously. Maybe Bob Bundy can come up with more helpful information.
Me, or the ugly man, whatever (3,3,6)
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Preferably today.
Can you give me some pointers, at least? How you solved this.
"If we wanna be great, we can't just sit on our hands" - 2017 NFL Bears draft
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Ok, but I wasn't looking for a proof with the answers in the beginning. I've gotten pretty far, but I need to find all the answers to
Last edited by !nval!d_us3rnam3 (2018-07-27 11:02:45)
"If we wanna be great, we can't just sit on our hands" - 2017 NFL Bears draft
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Ok, but I wasn't looking for a proof with the answers in the beginning. I've gotten pretty far, but I need to find all the answers to
EDIT: With a rigorous demonstration that this is the answer.
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Let us apply zetafunc’s method in another way. Dividing by 2 and rearranging gives
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Now consider the following table:
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Thus we see that outside of {0,±1} the equation has no solution as the LHS and RHS have opposite signs. This proves that there are no solutions other than x = 0, ±1.
Me, or the ugly man, whatever (3,3,6)
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