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Calculate
Since 0<x<1 we notice that:
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Last edited by Grantingriver (2018-12-15 04:06:22)
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In the previous solution, we have taken the average of the denominator as the weight in the summation which provides a good approximation of the limit, but it does not produce the exact solution. To get a more exact solution we should take as the weight in the summation the average of the whole fraction in the integrand. This follows from the following argument:
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In fact the "exact" solution can be obtained by the following argument:
which is the exact value of the limit. (sorry for the confusion)
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