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Question : An automatic machine fills plastic bags with a mixture of beans and vegetables. Most of the bags contain correct weight but because of the variation in size of beans and other vegetables a packet might be underweight , Overweight . A check of 4000 packets filled in the past month revealed
weights No of packets
Under 100
Satisfactory 3600
Over 300
1) What is the probability that if we select a packet it would be satisfactory (3600/4000)
2) Can a packet be underweight or overweight at same time
Question : Four coins are tossed simultaneously . What is the probability distribution for number of heads.
Question : An automatic machine fills plastic bags with a mixture of beans and vegetables. Most of the bags contain correct weight but because of the variation in size of beans and other vegetables a packet might be underweight , Overweight . A check of 4000 packets filled in the past month revealed
weights No of packets
Under 100
Satisfactory 3600
Over 300
1) What is the probability that if we select a packet it would be satisfactory (3600/4000)
2) Can a packet be underweight or overweight at same time
1) 3600/4000 = 36/40 = 9/10.
2) No.
Question : Four coins are tossed simultaneously . What is the probability distribution for number of heads.
HHHH, HHHT, HHTH, HTHH, HHTT, HTTT, HTHH, HTTT, THHH, THTT etc.
All heads : 1
3 heads : 3
In a similar way, 2 heads and 1 heads can be found.
All tails would be TTTT.
At least 1 head :
1 coin : 1/2 : 0.5 : 50%;
2 coins : 3/4 : 0.75 : 75%;
3 coins : 7/8 : 0.875 : 87.5%;
4 coins : 15/16 : 0.9375 : 93.75%.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Question : Four coins are tossed simultaneously . What is the probability distribution for number of heads.
ANSWER : Write sample space
HHHH THHH
HHHT THHT
HHTH THTH
HHTT THTT
HTHH TTHH
HTHT TTHT
HTTH TTTH
HTTT TTTT
then calculate for heads
N # outcomes with N heads probability to get N heads
0 1 1/16 = 0.0625
1 4 4/16 = 1/4 = 0.25
2 6 6/16 = 3/8 = 0.375
3 4 4/16 = 1/4 = 0.25
4 1 1/16 = 0.0625
Malik
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