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how to prove that a squared = b squared + c squared - 2 b c cos A in any triangle
hi ashraf
Welcome to the forum.
It comes directly from the dot or scalar product.
https://www.mathsisfun.com/algebra/vect … oduct.html
so
Bob
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make up a straight triangle with angle A and line c and you can arrive at this equation:
aa - (b-cCosA)^2 = cSinASinA
using Gougu theorem.
This equation is equivalent to the theorem you mentioned.
X'(y-Xβ)=0
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If A > pi/2 however, CosA = - Cos(pi-A)
Make up the angle Cos(pi-A) by extending b or c until you form a straight triangle with C or B and a
You then have a bigger straight triangle and a smaller one sharing the same straight line which can be calculated using SinA
Samiliar calculation goes and you will arrive at the same equation.
X'(y-Xβ)=0
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