Math Is Fun Forum
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#1 2019-12-02 23:10:04
- alex77
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- Registered: 2019-12-02
- Posts: 8
Hard exercise with positive terms
https://ibb.co/CmVWqm1
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#2 2019-12-10 02:55:18
- alex77
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- Registered: 2019-12-02
- Posts: 8
Re: Hard exercise with positive terms
No one?
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#3 2019-12-12 19:24:18
- George,Y
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- Registered: 2006-03-12
- Posts: 1,379
Re: Hard exercise with positive terms
I suggest you first thing first, simplify the fraction
i.e. k^(1/3)/k^2 = k^(-5/3)
Then you can try add them together?
X'(y-Xβ)=0
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