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Water is leaking out of a swimming pool that measures 20 ft by 40 ft by 6 ft. The amount of water in the pool at a time t is W(t) = 35,000 − 20t^2 gallons, where t equals the number of hours since the pool was last filled. At what rate is the
water leaking when t = 2h?
NOTE: I am not seeking the answer but the set up only. I will do the math work.
Thank you.
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Find dW/dt and then put in the given t value.
B
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Find dW/dt and then put in the given t value.
B
Hello Bob.
Let me see.
dW/dt = d/dt [35,000 − 20t^2]
dW/dt = -40t
What do I do with dW/dt?
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Bob wrote:Find dW/dt and then put in the given t value.
B
Hello Bob.
Let me see.
dW/dt = d/dt [35,000 − 20t^2]
dW/dt = -40t
What do I do with dW/dt?
Plug t=2 hours into dW/dt as the problem tells you to.
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May bobbym have a wonderful time in the pearly gates of heaven.
He will be sorely missed.
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mathland wrote:Bob wrote:Find dW/dt and then put in the given t value.
B
Hello Bob.
Let me see.
dW/dt = d/dt [35,000 − 20t^2]
dW/dt = -40t
What do I do with dW/dt?
Plug t=2 hours into dW/dt as the problem tells you to.
Ok. Very easy to do when someone explains what is going on.
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