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Write y as a function of x. Find dy/dx using
the Chain Rule.
1. y = u^3, u = 3v^2 + 1, v = 4/x2
2. y = u^2 + 1, u = 4/v
v = x^2
For both problems, I need to find
dy/dx = (dy/du)(du/dv)(dv/dx)
Can someone get me started on each question?
Thanks
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Start by doing the three differentiations.
'Chain' then together to create an expression for dy/dx.
Maybe you could stop at that, but I expect you should also put the final answer in terms of x only (if possible).
So eliminate 'u' by writing any u bits in terms of v. Simplify if poss.
Then eliminate v by writing any v bits in terms of x.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Start by doing the three differentiations.
'Chain' then together to create an expression for dy/dx.
Maybe you could stop at that, but I expect you should also put the final answer in terms of x only (if possible).
So eliminate 'u' by writing any u bits in terms of v. Simplify if poss.
Then eliminate v by writing any v bits in terms of x.
Bob
You said:
"So eliminate 'u' by writing any u bits in terms of v. Simplify if poss.
Then eliminate v by writing any v bits in terms of x."
What do you mean here?
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Please post your answer as far as you have got.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Please post your answer as far as you have got.
Bob
I will show my work here from now on, wrong or right.
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