You are not logged in.
Just need some help understanding some of these math problems and checking the ones I already did (if right/wrong). Thank you for your time:
1. An equilateral triangle with a side of 1 inch - Answer: A
A 0.43 sq in
B 0.56 sq in
C 0.89 sq in
D 0.23 sq in
E 0.19 sq in
F 0.54 sq in2. A square with a side of 2 feet - Answer: B
A 9 sq ft
B 4 sq ft
C 2 sq ft
D 7 sq ft
E 3 sq ft
F 8 sq ft3. A regular pentagon with a side of 3 centimeters - Answer: F
A 23.01 sq cm
B 12.34 sq cm
C 39.17 sq cm
D 9.46 sq cm
E 34.21 sq cm
F 15.48 sq cm4. A regular hexagon with a side of 10 cm - Answer: D
A 641.25 sq cm
B 194.45 sq cm
C 361.25 sq cm
D 259.81 sq cm
E 105.22 sq cm
F 453.01 sq cm5. A regular heptagon with a side of 7 inches. ***need help understanding how to solve***
A 178.06 sq in
B 294.16 sq in
C 169.21 sq in
D 358.91 sq in
E 157.36 sq in
F 277.91 sq in6. A trapezoid where the height is 18 cm, base 1 = 16 cm and b2 = 8 cm. - Answer: C
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 230 sq cm
E 280.9 sq cm
F 510 sq cm7. A trapezoid where the height = 7 mm, base 1 = 26 mm and base 2 = 9 mm. - Answer: B
A 178.06 sq mm
B 122.5 sq mm
C 216 sq mm
D 230 sq mm
E 28.9 mm
F 510 mmFill in the missing information for the following trapezoids:
8.
height = 19.8 cm
b1 = ________
b2 = 14.4 cm
area = 401.94 cm2 - Answer: A
A 26.2 cm
B 12.5 cm
C 216 cm
D 23 cm
E 28.9 cm
F 51 cm9.
height = 23 mm
b1 = 23 mm
b2 = ________
area = 529 mm2 - Answer: D
A 78.06 sq mm
B 22.5 sq mm
C 21.6 mm
D 23 mm
E 28.9 mm
F 30 mm^210.
height = ________
b1 = 20 cm
b2 = 21 cm
area = 205 cm2 - Answer: D
A 17.06 cm
B 12.5 sq cm
C 26 cm
D 10 cm
E 28.9 cm
F 50 cm^211.
height = 28.9 m
b1 = 26.9 m
b2 = ________
area = 806.31 m^2 - Answer: EA 17.06 sq m
B 15 m
C 46 m
D 23 m
E 28.9 m
F 51 m12. If the area of a parallelogram is 690.84 m^2 and the height is 20.2 m, what is the length of the base? - Answer: D
A 78.06 m
B 22.5 m
C 216 m
D 34.2 m
E 28.9 m
F 51 m13. If the base of a rectangle is 28 cm and the area is 588 cm^2, what is the height of the rectangle? - Answer: E
A 17.06 cm
B 122.5 sq cm
C 216 sq cm
D 23 cm
E 21 cm
F 51 cm^214. If the height of a rectangle is 26.1 m and the base is 17.3 m, what is the area of the rectangle? - Answer: A
A 451.53 m^2
B 122.5 m^2
C 216 m^2
D 430 m^2
E 289 m^2
F 510 m^215. If the height of a parallelogram is 34 cm and the base is 15 cm, what is the area of the parallelogram? - Answer: F
A 178.06 cm^2
B 122.5 cm^2
C 216 cm^2
D 230 cm^2
E 289 cm^2
F 510 cm^216. What is the area of a parallelogram with height 26 cm, base 16 cm, and side length 28 cm?***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 416 cm^2
E 28.9 cm
F 510 cm^217. What is the area of a regular octagon with a side of 6 cm? ***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 23 cm^2
E 173.82 cm^2
F 510 cm^218. What is the area of this polygon?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area1.gifls_XF = 53 mm ls_XV = 72 mm ls_VR = 16 mm
ls_FB = 31 mm ls_BT = 31 mm ls_EU = 47 mm
ls_UL = 31 mm ls_TL = 88 mm ls_DE = 16 mm
ls_RM = 70 mm ls_MC = 21 mm ls_DC = 70 mmA 8014 mm2
B7030 mm2
C6027 mm2
D5478 mm2
E 1782 mm2
F 1225 mm219. What is the area of this rectangle?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area2.jpgA 17.06 sq units
B60 sq units
C21.6 sq units
D53 sq units
E 28.9 sq units
F 51 sq units20. What is the area of this polygon?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area3.jpgA 178 sq units
B129 sq units
C230 sq units
D240 sq units
E 219 sq units
F 206 sq units
1. Post no more than two problems at a time. Give tutors a chance to reply.
2. Show your effort, your math work. By doing so, it helps the tutors here to know where you stand, mathematically speaking.
3. I like your questions but please be specific in terms of directions. For example, don't say this: y = mx + b. Help. What? Help in what way? This is just an example.
4. Give tutors a chance to reply. Many tutors work full-time and NO ONE HERE is getting paid to help out with hundreds of daily questions. I myself use the site as a tutor and as a person learning mathematics.
5. What grade are you in? What math course are you taking?
Offline
3 things,
1. This was from about 8 years ago
2. The question being asked right now is only asking for one of the questions not all.
3. I dont think the original poster is active anymore
Hope this helps
I wish thee not, yet it is always -Anonymous
Offline
3 things,
1. This was from about 8 years ago
2. The question being asked right now is only asking for one of the questions not all.
3. I dont think the original poster is active anymore
Hope this helps
Thanks for clearing this up for me.
Offline
hi Peccatrix123
I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?
If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD make a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
hi Peccatrix123
I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD make a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
Hello Bob. About how many questions belong to the Unanswered section? Does it make sense to answer unanswered questions posted prior to the current year?
Thanks.
P. S. I really think this forum would benefit more if it was divided by courses. This is simply my opinion. Take a look at freemathhelp.com or mathhelpboard.com and others like it.
Offline
hi Peccatrix123
I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD makes a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right-angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
Hello sir,
Using pythag, I solved for AF which I got 9. Then I solved for the area of the triangle(0.5 x12x9) which I got 54. For the area of the rectangle EAFD, I'm confused. What is FD? I know EA is 8, but do I have to use pythag also to find FD?
Thanks,
J
Last edited by Peccatrix123 (2021-05-14 04:56:35)
Do with what you have, until you do with what you want.
-J
Offline
hi J
%4 is good for the triangle.
Shape EAFD is a rectangle. EA was given as 8. AF = AB + BF.
You got 9 for BF (although you wrote AF). So AF = 10 + 9.
Nearly there.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
hi J
%4 is good for the triangle.
Shape EAFD is a rectangle. EA was given as 8. AF = AB + BF.
You got 9 for BF (although you wrote AF). So AF = 10 + 9.
Nearly there.
Bob
Hello Sir,
So the area of the rectangle EAFD would be 152(8x19)
Now I would add both areas together which would be:
152+54=206
So my final answer would be 206
Do with what you have, until you do with what you want.
-J
Offline
Correct! Well done!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
Thank you very much, Sir! Have a good day and thank you for helping so many people with math free of charge!
Do with what you have, until you do with what you want.
-J
Offline
You're welcome.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline