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Hello,
I need help with this exercise.
A ball is launched upward at a speed of 20 meters per second (m/s) from a 60-meter tall platform. The equation for the ball’s height (h in meters) at time t seconds after launch is h = -4.9t2 + 20t + 60. How long before the ball hits the ground?
Best,
Jade
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Heya Jade,
I'm going to answer this thread(and not the other one, as the details appear to be the same.)
To determine when the ball hits the ground, solve the equation when h equals 0.
You can either complete the sqiare or use the quadratic formula. For the sake of simplicity, I'm going to proceed using the latter method, but either one is fine.
Last edited by Mathegocart (2022-07-04 09:11:09)
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