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19. And the length of the shortest leg is √(12), what is the length of the longest leg?
A. 29
B. 6
C. 38
D. 56
E. 61
F. 17
For this question I got B, but it doesn't work with question 20.
20. Working from #19, what is the length of the hypotenuse?
A. 8.4197
B. 1.9764
C. 10.5742
D. 6.2414
E. 2.4971
F. 6.9282
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this is a 30-50-90 triangle by the way !
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Hi undertaker,
Welcome to the forum!
How can there be a 30-50-90 degrees triangle? The sum must always be 180°.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Whoops sorry, I meant 30-60-90!
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hi undertaker
Welcome to the forum.
If you have an equilateral triangle, ABC, all sides are equal and so are all three angles. Suppose the sides are each 2 units long. The angles are 60-60-60.
Draw a line from A to the midpoint, D, of BC. This line is a line of symmetry, so we have the following:
AB = 2, BD = 1, angle ABD = 60, angle BAD = 30, angle ADB = 90.
So triangle ABD is right angled with angles 30-60-90, and sides 2 and 1. The third side, AD can be calculated using Pythagoras' theorem.
[math]AD^2 = 2^2 - 1^2 = 3 \implies AD = \sqrt{3}[math]
Thus cos ABD = cos 60 = BD/AB = 1/2 = sin 30
Sin ABD = sin 60 = AD/AB = √3/2 = cos 30
and tan ABD = tan 60 = AD/BD = √3/1 = √3 so tan 30 = 1/√3
Although I started with a 2-2-2 equilateral, it would also be true for any similar shaped triangle such as the one in question 19.
Noticing that Q20 wants the hypotenuse I'll assume they mean BD = √12 and they want AD. You can calculate this using tan 60 = AD/BD.
And question 20 using sin 60 = AD / AB.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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