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I would like to intersect the function y=(a^n-x^n-z^n)^(1/n),
which describes a sphube, being a rounded cube with its center in the origin,
with the line, going trough the origin and P=(1|1|1).
I tried it with y=x+z and y=3-x-z,
but the computer says I'm giving planes.
Is it possible to somehow get the point, where they intersect ?
For numericals, one could take a=1 and n=4.
Edit: Being unsure what the correct equation for the line is.
Last edited by mathdrop (2023-01-18 07:09:41)
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hi mathdrop
It looks like you've got
The line joining the origin to (1,1,1) is
So every point on the line has x = y = z
So it will intersect the shape at
Hope that helps,
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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3*x^4=1 where x=y=z
x=y=z=+/- 1/3^(1/4)≈+/- 0.75984
Your point hits the shape :-)
How have you gotten 3*x^4=1 ?
I moved everything to one side:
x^4+y^4+z^4-1=0
f*x+f*y+f*z-r=0
Set them equal:
x^4+y^4+z^4-1=f*x+f*y+f*z-r
And tried to solve the above for x,
but this gave me wild formulas.
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If the line goes through (0,0,0) and (1,1,1) then its equation is
and so for a given lambda x=y=z.
Replace y and z with x and you get
Trying to solve with x, y, and z being maybe different makes the algebra horrible but as they are equal it's enough to solve 3x^4 = 1 which you have done.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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