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## #1 2023-09-25 01:40:07

sologuitar
Member
Registered: 2022-09-19
Posts: 467

### Factor Completely

Factor completely.  If the polynomial cannot be factored, say it is prime.

x^6 + 2x^3 + 1

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## #2 2023-09-25 04:12:43

Bob Registered: 2010-06-20
Posts: 9,863

### Re: Factor Completely

We're in luck here because (x^3)^2 = x^6

So substitute Y = x^3 and you'll get a quadratic in Y.

Bob

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob Offline

## #3 2023-09-25 12:10:00

sologuitar
Member
Registered: 2022-09-19
Posts: 467

### Re: Factor Completely

Bob,

Thank you. You said we're in luck in this case because (x^3)^2 = x^6.
What if the question is not so obvious? What then?

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## #4 2023-09-25 14:31:05

amnkb
Member
Registered: 2023-09-19
Posts: 175

### Re: Factor Completely

harpazo1965 wrote:

Factor completely.  If the polynomial cannot be factored, say it is prime.

x^6 + 2x^3 + 1

Bob wrote:

We're in luck here because (x^3)^2 = x^6

harpazo1965 wrote:

You said we're in luck in this case because (x^3)^2 = x^6.
What if the question is not so obvious? What then?

then maybe it cant be factored, right?
if your doing perfect sqares then it has to fit into perfect aquare pattern

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## #5 2023-09-26 01:44:50

sologuitar
Member
Registered: 2022-09-19
Posts: 467

### Re: Factor Completely

Bob wrote:

We're in luck here because (x^3)^2 = x^6

So substitute Y = x^3 and you'll get a quadratic in Y.

Bob

Let me see.

Rewrite x^6 as (x^3)^2.

Let u = x^3

u^2 + 2u + 1

Factor.

(u + 1)(u + 1)

Back-substitute for u.

(x^3 + 1)(x^3 +1)

The sum of cubes tells me that (x^3 + 1) is the same thing as
(x + 1)(x^2 - x  + 1).

My answer is (x + 1)(x^2 - x + 1)^2.

Textbook answer is (x + 1)^2(x^2 - x + 1)^2.

Who is right and why?

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## #6 2023-09-26 06:59:50

amnkb
Member
Registered: 2023-09-19
Posts: 175

### Re: Factor Completely

harpazo1965 wrote:

Rewrite x^6 as (x^3)^2.

Let u = x^3

u^2 + 2u + 1

Factor.

(u + 1)(u + 1)

Back-substitute for u.

(x^3 + 1)(x^3 +1)

The sum of cubes tells me that (x^3 + 1) is the same thing as
(x + 1)(x^2 - x  + 1).

My answer is (x + 1)(x^2 - x + 1)^2.

Textbook answer is (x + 1)^2(x^2 - x + 1)^2.

Who is right and why?

in the red part you have

in the blue part you factored

then replace

the aquare goes on both factors inside
once you do that youll match the books answer

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## #7 2023-09-26 13:34:53

sologuitar
Member
Registered: 2022-09-19
Posts: 467

Thank you.

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