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**sologuitar****Member**- Registered: 2022-09-19
- Posts: 467

Solve 1/a = 1/b + 1/c

I think the first step is to multiply both sides of the equation by ABC.

(abc)(1/a) = (abc)(1/b + 1/c)

bc = ac + ab

Is this OK so far?

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**Jai Ganesh****Administrator**- Registered: 2005-06-28
- Posts: 44,437

In the right path.

It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**amnkb****Member**- Registered: 2023-09-19
- Posts: 176

sologuitar wrote:

Solve 1/a = 1/b + 1/c

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**sologuitar****Member**- Registered: 2022-09-19
- Posts: 467

amnkb wrote:

sologuitar wrote:Solve 1/a = 1/b + 1/c

Thanks but I didn't ask you to solve for c.

I often find myself going through a textbook like walking in the park on a sunny day. I then reach a certain chapter or section that requires knowledge of all the previous math material I have learned or thought I learned. Confusion sets in to create a stumbling block that keeps me wondering if I truly learned anything at all in my previous math courses or chapters or sections that I just completed. Why does this happen? How do I keep myself from forgetting the earlier chapters or sections in math textbooks?

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