Math Is Fun Forum

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Maximum Average Cost

The maximum average cost per hour in dollars, C bar, of producing x riding lawn mowers can be modeled by the function

C bar = 0.3x^2 + 21x - 251 + (2500/x)

A. Graph C bar = C bar (x)

B. Determine the number of riding lawn mowers to produce in order to minimize average cost.

C. What is the minimum average cost?

Note:

1. There is a bar over C. This is why I say C bar here.

2. Do not use calculus.

3. Can someone graph this function for me here?

4. I seek the steps for B and C.

Last edited by mathxyz (2024-03-23 05:28:58)

Bob

Administrator

Registered: 2010-06-20

Posts: 10,640

Re: Maximum Average Cost

You can see the minimum. B is just the x value at that point and y is the cost at the minimum.

Bob

---

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Re: Maximum Average Cost

https://i.imgur.com/Z1NtBFh.png

You can see the minimum. B is just the x value at that point and y is the cost at the minimum.

Bob

The say B = 10 riding lawn mowers per hour.

I say C = y coordinate at the point that = 10 for x.
I say about $239....