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1. Show that a constant f(x) = b has an average rate of change of zero.
2. Compute the average rate of change of y = sqrt{4 - x^2} on the interval [-2, 2]. Explain how this can occur.
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This is another secant question.
Rate of change means how y is varying with x so it's a gradient that is needed.
For the first part do the usual x and x+h thing. You should find that the secant function simplfies to zero.
For the second part work out y1 when x = -2 and y2 when x = +2
Then get the gradient of the line joining these two points.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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This is another secant question.
Rate of change means how y is varying with x so it's a gradient that is needed.
For the first part do the usual x and x+h thing. You should find that the secant function simplfies to zero.
For the second part work out y1 when x = -2 and y2 when x = +2
Then get the gradient of the line joining these two points.
Bob
In place of using the difference quotient, can I take the derivative the y = sqrt{4 - x^2} as step one?
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Because 1 says 'show' just saying what the derivative is would not be enough.
For 2, differentiation wouldn't work because an average is asked for.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Because 1 says 'show' just saying what the derivative is would not be enough.
For 2, differentiation wouldn't work because an average is asked for.
Bob
Ok. I will use the difference quotient to follow through with this problem.
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