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In Section 3.5 in my College Algebra textbook, I came across a very interesting question with three parts. My work is wrong. My answers are incorrect. However, I will show my work and reveal the correct point answer for each part at the end of my computation.
Suppose (-3, 5) is a point on the graph of y = g(x).
A. What point is on the graph of y = g(x + 1) - 3?
B. What point is on the graph of y = -3g(x - 4) + 3?
C. What point is on the graph of y = g(3x + 9)?
For A:
Let y = g(x) = 5
y = g(x + 1) - 3
5 = g(-3 + 1) - 3
5 = g(-2) - 3
5 + 3 = g(-2)
8 = g(-2)....This leads to the point (-2, 8).
The textbook answer is (-4, 2).
How do I compute the correct point?
For B:
Let y = g(x) = 5
y = -3g(x - 4) + 3
g(x) = -3g(-3 - 4) + 3
5 = -3g(-7) + 3
5 - 3 = -3g(-7)
2 = -3g(-7)
-2/3 = g(-7)....This leads to the point (-7, -2/3).
The textbook answer is (1, -12)?
How do I compute the correct point?
For C:
Let y = g(x) = 5
y = g(3x + 9)
g(x) = g(3(-3) + 9)
5 = g(0)....This leads to the point (0, 5).
The textbook answer is (-4, 5).
How do I compute the correct point?
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A. (x+1) inside the function bracket will move the graph one place left. The -3 outside the bracket moves the point down 3.
B. (x-4) moves the point 4 places right. That gives you g(1-4) which evaluates to 5. The times by -3 and add 3 to get the new y coordinate.
C. I know g(-3) so I put 3x+9 = -3 => 3x = -12 => x = -4. So we then have g(3.(-4)+9) = g(-12+9) = g(-3) = 5. The y cordinate remains at 5.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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A. (x+1) inside the function bracket will move the graph one place left. The -3 outside the bracket moves the point down 3.
B. (x-4) moves the point 4 places right. That gives you g(1-4) which evaluates to 5. The times by -3 and add 3 to get the new y coordinate.
C. I know g(-3) so I put 3x+9 = -3 => 3x = -12 => x = -4. So we then have g(3.(-4)+9) = g(-12+9) = g(-3) = 5. The y cordinate remains at 5.
Bob
Thank you for correcting my work.
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